Timeline for Hilbert class field of Quadratic fields
Current License: CC BY-SA 3.0
8 events
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Jan 23, 2021 at 14:30 | history | edited | GH from MO |
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Jan 23, 2021 at 14:19 | answer | added | Davood Khajehpour | timeline score: 1 | |
Sep 28, 2011 at 12:49 | comment | added | Cam McLeman | For your second question, the answer is no by genus theory: The more primes that divide d, the bigger the class group. | |
Sep 28, 2011 at 12:37 | comment | added | Tommaso Centeleghe | Observe that the ring of Integers of $Q(\sqrt{-d})$ when $d\equiv 1$ mod $4$ is not a UFD because the only ideal lying above $2$, which is ramified, cannot be principal (the integer $2$ is not a norm). The theory of complex multiplication (in case you did not know) relates the Hilbert class field of an imaginary quadratic filed K to the j-invariant of any elliptic curve with CM by the integers of K (one can learn this in "Primes of the form x^2+ny^2" by D.cox) | |
Sep 28, 2011 at 12:21 | history | edited | Sina | CC BY-SA 3.0 |
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Sep 28, 2011 at 12:18 | comment | added | Emerton | It is not true that $\mathbb Q(\sqrt{d},i)$ is the Hilbert Class Field of $\mathbb Q(\sqrt{-d})$ in general when $4 | (d-1)$, just that it is contained in the Hilbert Class Field. | |
Sep 28, 2011 at 11:39 | comment | added | Dror Speiser | A book dedicated to this question is Cohen's Advanced Topics in Computational Number Theory. | |
Sep 28, 2011 at 11:12 | history | asked | Sina | CC BY-SA 3.0 |