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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Nov 15, 2011 at 16:12 vote accept Moosbrugger
Oct 7, 2011 at 11:09 answer added Donu Arapura timeline score: 4
Oct 7, 2011 at 8:36 comment added Leo Alonso I've retagged it. I hope this will give more visibility to the question.
Oct 7, 2011 at 8:35 history edited Leo Alonso
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Oct 7, 2011 at 8:34 history edited Leo Alonso
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Oct 7, 2011 at 8:33 history edited Leo Alonso
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Oct 7, 2011 at 3:07 answer added Emerton timeline score: 4
Sep 28, 2011 at 12:19 comment added Moosbrugger I think at least the Hodge filtration should be. The weight filtration is of a somewhat more Betti-origin, so I wouldn't be so surprised to find an example where it's not geometric in this way. But it's quite non-trivial to extract anything like this from Saito -- the set-up uses polarizations (and therefore the real numbers) in a quite non-trivial way.
Sep 28, 2011 at 6:46 comment added Emerton Dear Moosbrugger, I wouldn't like to try and prove it, but if $M$ is of geometric origin over $K$, then I think that both the Hodge and the weight filtrations should be defined over $K$. Regards, Matthew
Sep 28, 2011 at 2:21 history asked Moosbrugger CC BY-SA 3.0