Timeline for Functoriality of adjugate matrix
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 27, 2011 at 13:57 | comment | added | joel | @Manny-Reyes: i know that $\mathbf{AA}^\mathrm D = \mathbf A^\mathrm D \mathbf A = (\det \mathbf A) \mathbf I$ which gives our result if $\mathbf A$ is invertible, because then $\mathbf{AA}^{-1} = \mathbf A^{-1} \mathbf A = \mathbf I$. | |
| Sep 27, 2011 at 13:56 | comment | added | Igor Rivin | @Manny: yes, that's correct. | |
| Sep 27, 2011 at 13:55 | comment | added | joel | i'll check it out right away—if it's possible would you be kind enough to explain in plain language (basic linear algebra if it's possible) how does action of exterior power works? :) thanks in advance for your effort! | |
| Sep 27, 2011 at 13:39 | comment | added | Manny Reyes | If the matrix is invertible, I think the adjugate would actually be the inverse times the determinant. Right? | |
| Sep 27, 2011 at 13:18 | history | answered | Igor Rivin | CC BY-SA 3.0 |