Timeline for Break polyhedron into tetrahedron
Current License: CC BY-SA 4.0
12 events
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Jun 29, 2022 at 13:36 | history | edited | Graviton | CC BY-SA 4.0 |
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Oct 8, 2014 at 12:16 | history | edited | user9072 |
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Dec 3, 2009 at 22:28 | comment | added | B. Bischof | I have a similar question with a slightly different motivation(maybe). Consider a convex n-polytope given by normal vectors with length determined as the (n-1)-volume of the "faces" and the vectors base point at the "center of mass" of the "faces" in general position. Can one determine the similarly defined normal vectors of the tetrahedrons if we decompose this polytope into (n-1)-tetrahedrons? I hope this short explanation is adequate. If necessary I can move this question to its own thread. | |
Dec 3, 2009 at 15:57 | answer | added | Joseph Malkevitch | timeline score: 5 | |
Dec 3, 2009 at 15:22 | vote | accept | Graviton | ||
Dec 3, 2009 at 15:20 | history | edited | Graviton | CC BY-SA 2.5 |
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Dec 3, 2009 at 14:52 | comment | added | Harry Gindi | This seems really homework-y. | |
Dec 3, 2009 at 14:39 | history | edited | Jason Dyer |
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Dec 3, 2009 at 14:36 | answer | added | Hugh Thomas | timeline score: 8 | |
Dec 3, 2009 at 12:27 | comment | added | Nurdin Takenov | Can we add additional vertices? It's important, because there are polyhedra which cannot be triangulated into tetrahedra without adding new vertices, such as Schönhardt polyhedron, en.wikipedia.org/wiki/Schönhardt_polyhedron | |
Dec 3, 2009 at 8:46 | comment | added | Yemon Choi | Context? More information of what you've already tried, or looked at? | |
Dec 3, 2009 at 8:37 | history | asked | Graviton | CC BY-SA 2.5 |