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Sep 21, 2011 at 6:29 comment added Laurent Moret-Bailly Right, but now quasifinite morphisms are assumed of finite type (see footnote at the same place in SGA1). For instance, $A\to\hat{A}$ is not quasifinite in general.
Sep 20, 2011 at 21:23 history answered Mahdi Majidi-Zolbanin CC BY-SA 3.0