Timeline for When is $A : C(X) \to C(Y)$ a composition operator?
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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S Feb 28, 2018 at 13:32 | history | suggested | Evgeny Kuznetsov | CC BY-SA 3.0 |
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Feb 28, 2018 at 13:06 | review | Suggested edits | |||
S Feb 28, 2018 at 13:32 | |||||
Dec 4, 2009 at 20:44 | answer | added | Oleg Eroshkin | timeline score: 4 | |
Dec 4, 2009 at 20:07 | history | edited | santker heboln |
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Dec 4, 2009 at 9:00 | answer | added | Matthew Daws | timeline score: 0 | |
Dec 3, 2009 at 8:21 | history | edited | Andrew Stacey | CC BY-SA 2.5 |
Converted maths to jsMath, two minor grammatical corrections
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Dec 3, 2009 at 3:18 | comment | added | Yemon Choi | Seeing as my general topology is, despite Kelley's injunction, pretty shoddy - what exactly is the interest in the particular hypotheses you've chosen? For instance, is it the case that these conditions (hemicompact k-space) are the weakest which allow one to detect properties of the space X from the algebra C_R(X), in some sense? Or are you just choosing some general conditions because they seem interesting to you? | |
Dec 2, 2009 at 21:12 | answer | added | Greg Kuperberg | timeline score: 3 | |
Dec 2, 2009 at 20:51 | history | edited | santker heboln | CC BY-SA 2.5 |
added 555 characters in body
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Dec 2, 2009 at 20:05 | comment | added | Matthew Daws | You must have missed something out: as written, couldn't I pick some (real-valued) measure $\mu$ on X and define $A:C(X)\rightarrow C(Y)$ by $A(f) = \mu(f) 1$. Then $A(\overline{f}) = \overline{A(f)}$ but $A$ would only be induced by a composition operator if $\mu$ were a point mass at $x_0$, with $T(y)=x_0$ for all $y\in Y$. If $A$ is also a homomorphism, then it's fine (and, AFAIK, you don't actually need it to be a $*$-homomorphism...) What is a hemicompact k-space? | |
Dec 2, 2009 at 17:32 | comment | added | Qiaochu Yuan | You should probably define all of your terms. | |
Dec 2, 2009 at 17:28 | history | asked | santker heboln | CC BY-SA 2.5 |