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Aug 23, 2016 at 19:37 comment added Jose Brox @Seva Sure, I should have thought before asking and see the obvious! Thank you
Aug 23, 2016 at 19:19 comment added Seva @Jose Brox: with any finite set $S\subset {\mathbb C}^n$ you can associate a set $T\subset {\mathbb R}^{2n}$ such that $|T|=|S|$ and $|S-S|=|T-T|$, cannot you?
Aug 23, 2016 at 18:52 comment added Jose Brox Are things very different over the complex numbers?
Sep 20, 2011 at 21:43 comment added Keenan Pepper I have no idea why I didn't come across this paper on my own, because I was using all those search terms. Now it should be easier for others to find.
Sep 20, 2011 at 21:40 vote accept Keenan Pepper
Sep 20, 2011 at 7:23 history answered Seva CC BY-SA 3.0