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Sep 20, 2011 at 5:21 history edited djv CC BY-SA 3.0
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Sep 20, 2011 at 5:20 comment added djv Yes, the tree is being used to do a variable resolution discretisation of the hypercube - so "important" areas have significantly more (and hence smaller) polytopes. Off the top of my head, the maximum volume ratio between the largest and smallest polytopes could be anywhere between $2^{10}$ or $2^{20}$. What you suggest seems fairly simple to implement, so I'll give it a try and see if it works alright. Thanks!
Sep 20, 2011 at 5:12 comment added Keenan Pepper Can't you just sample points uniformly from the entire hypercube, discarding points in polytopes which already have enough points? The only reason this would be inefficient is if your polytopes have widely differing (hyper)volumes. Do they?
Sep 20, 2011 at 4:35 history asked djv CC BY-SA 3.0