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Sep 29, 2011 at 17:01 vote accept name
Sep 27, 2011 at 18:52 answer added Jizhan Hong timeline score: 1
Sep 26, 2011 at 17:42 comment added name Hi, thanks for your comment! As is often the case, I forgot one of my hypotheses: $K$ is finitely generated as a field over $k$. Also, as an aside, I was using Samuel-Zariski's definition of discrete page 48-49.
Sep 25, 2011 at 15:53 comment added Jizhan Hong Your definition of 'discrete valuation' is not the usual definition. Usually if one says 'DVR', then one means a valuation with its value group isomorphic to $\mathbb{Z}$. If one says 'discrete valuation' in the general sense, then one means the value group is discrete as an ordered group, i.e. every element has a predecessor and a successor; in this case the value group could also be $\mathbb{Z}\times\mathbb{Q}\times\cdots$. That being said, S′ could be empty if all the valuations are with divisible value groups, as in the case of separably/real/radically closed fields.
Sep 18, 2011 at 9:35 history edited name CC BY-SA 3.0
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Sep 18, 2011 at 7:06 history asked name CC BY-SA 3.0