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Jun 24, 2016 at 0:47 answer added yakov timeline score: -1
Jun 24, 2016 at 0:35 comment added yakov If a nonabelian $p$-group $G$ has an abelian sugroup of index $p$, then $|G|=p|G'||\text{Z}(G)$. Therefore, if $|G'|=p$, then $|G:\text{Z}(G)|=p^2$.
Dec 20, 2015 at 17:04 answer added Yakov timeline score: 0
Sep 18, 2011 at 13:46 history edited Ralph
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Sep 18, 2011 at 13:46 history edited Ralph
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Sep 18, 2011 at 13:38 answer added Ralph timeline score: 4
Sep 17, 2011 at 21:12 answer added Leandro Vendramin timeline score: 0
Sep 17, 2011 at 21:06 comment added Sonia Balagopalan According to GAP, SmallGroup(32,22) has a centre of order 8, and the derived subgroup has order 2.
Sep 16, 2011 at 18:45 history asked Nik CC BY-SA 3.0