Timeline for Maximum value of the number of conjugacy classes of nonabelian p-groups with an abelian subgroup of index p
Current License: CC BY-SA 3.0
9 events
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Jun 24, 2016 at 0:47 | answer | added | yakov | timeline score: -1 | |
Jun 24, 2016 at 0:35 | comment | added | yakov | If a nonabelian $p$-group $G$ has an abelian sugroup of index $p$, then $|G|=p|G'||\text{Z}(G)$. Therefore, if $|G'|=p$, then $|G:\text{Z}(G)|=p^2$. | |
Dec 20, 2015 at 17:04 | answer | added | Yakov | timeline score: 0 | |
Sep 18, 2011 at 13:46 | history | edited | Ralph |
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Sep 18, 2011 at 13:46 | history | edited | Ralph |
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Sep 18, 2011 at 13:38 | answer | added | Ralph | timeline score: 4 | |
Sep 17, 2011 at 21:12 | answer | added | Leandro Vendramin | timeline score: 0 | |
Sep 17, 2011 at 21:06 | comment | added | Sonia Balagopalan | According to GAP, SmallGroup(32,22) has a centre of order 8, and the derived subgroup has order 2. | |
Sep 16, 2011 at 18:45 | history | asked | Nik | CC BY-SA 3.0 |