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David White
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If you work with a single associative algebra $A$, then there is not so much senssense to try to define a notion of $A$-tri-module. Namely, $A$-bimodules appear naturally as operadic $A$-modules.


To give you a picture, an associative algebra $A$ is in particular an algebra over the colored operad given by intervals of the real line and thirtheir disjoint union inclusions (a-k-a prefactorization algebras on the real line).

It has the property to be locally constant: the space associated to any interval is the same ($A$ itself).

Let me now relax a bit this locally constant property. Assume that you have such a (pre)factorization algebra over the real line such that it is locally constant outside the origin. Then you will get two associative algebras (one from $(0,+\infty)$ and the other from $(-\infty,0)$) together with a bunch of bimodules (One for each interval containing the origin).

There is nothing against the idea of having a factorization algebra on the graph consisting of three half-edges attached to a single vertex. Things like this might have appeared in $2d$ lattice models.

If you work with a single associative algebra $A$, then there is not so much sens to try to define a notion of $A$-tri-module. Namely, $A$-bimodules appear naturally as operadic $A$-modules.


To give you a picture, an associative algebra $A$ is in particular an algebra over the colored operad given by intervals of the real line and thir disjoint union inclusions (a-k-a prefactorization algebras on the real line).

It has the property to be locally constant: the space associated to any interval is the same ($A$ itself).

Let me now relax a bit this locally constant property. Assume that you have such a (pre)factorization algebra over the real line such that it is locally constant outside the origin. Then you will get two associative algebras (one from $(0,+\infty)$ and the other from $(-\infty,0)$) together with a bunch of bimodules (One for each interval containing the origin).

There is nothing against the idea of having a factorization algebra on the graph consisting of three half-edges attached to a single vertex. Things like this might have appeared in $2d$ lattice models.

If you work with a single associative algebra $A$, then there is not so much sense to try to define a notion of $A$-tri-module. Namely, $A$-bimodules appear naturally as operadic $A$-modules.


To give you a picture, an associative algebra $A$ is in particular an algebra over the colored operad given by intervals of the real line and their disjoint union inclusions (a-k-a prefactorization algebras on the real line).

It has the property to be locally constant: the space associated to any interval is the same ($A$ itself).

Let me now relax a bit this locally constant property. Assume that you have such a (pre)factorization algebra over the real line such that it is locally constant outside the origin. Then you will get two associative algebras (one from $(0,+\infty)$ and the other from $(-\infty,0)$) together with a bunch of bimodules (One for each interval containing the origin).

There is nothing against the idea of having a factorization algebra on the graph consisting of three half-edges attached to a single vertex. Things like this might have appeared in $2d$ lattice models.

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DamienC
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If you work with a single associative algebra $A$, then there is not so much sens to try to define a notion of $A$-tri-module. Namely, $A$-bimodules appear naturally as operadic $A$-modules.


To give you a picture, an associative algebra $A$ is in particular an algebra over the colored operad given by intervals of the real line and thir disjoint union inclusions (a-k-a prefactorization algebras on the real line).

It has the property to be locally constant: the space associated to any interval is the same ($A$ itself).

Let me now relax a bit this locally constant property. Assume that you have such a (pre)factorization algebra over the real line such that it is locally constant outside the origin. Then you will get two associative algebras (one from $(0,+\infty)$ and the other from $(-\infty,0)$) together with a bunch of bimodules (One for each interval containing the origin).

There is nothing against the idea of having a factorization algebra on the graph consisting of three half-edges attached to a single vertex. Things like this might have appeared in $2d$ lattice models.