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Sep 17, 2011 at 19:42 comment added Alex Suciu Actually, the group ${\rm SL}(2,\mathbb{Z})$ decomposes as a free product with amalgamation, of the form $\mathbb{Z}_4*_{\mathbb{Z}_2} \mathbb{Z}_6$. Thus, the complete list of finite orders of elements in this group is $\{1, 2, 3, 4, 6\}$.
Sep 15, 2011 at 20:00 vote accept Ying Zhang
Sep 15, 2011 at 16:23 history answered naf CC BY-SA 3.0