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May 6, 2013 at 7:18 history edited Georges Elencwajg CC BY-SA 3.0
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Sep 14, 2011 at 10:22 comment added Georges Elencwajg I really appreciate the kind words, Donu, especially from you. Thanks!
Sep 14, 2011 at 9:16 comment added Georges Elencwajg Dear ulrich, you are right of course: $\mathbb C[\epsilon ]/(\epsilon^2)$ is flat, over $\mathbb C$, like any algebra over a field! I have reversed the arrow and since I was at it, added a short justification of non-flatness. Sincere thanks for your attention, ulrich!
Sep 14, 2011 at 9:13 history edited Georges Elencwajg CC BY-SA 3.0
Completely modified b)
Sep 14, 2011 at 8:47 comment added Donu Arapura Georges, I wish I had this list when I was a student. But at least I have it now.
Sep 14, 2011 at 5:08 comment added naf I think the map in b) is flat. Perhaps the arrow should be reversed?
Sep 14, 2011 at 1:02 comment added Georges Elencwajg Dear Qing, thank you for the kind words and the corrections. Actually, even if $Y$ were connected, what I wrote in a) would have been false for $X=Y$. So in I have corrected my answer by explicitly requesting that the closed set $Y$ not be open .
Sep 14, 2011 at 0:54 history edited Georges Elencwajg CC BY-SA 3.0
made corrections suggested by Qing Liu
Sep 14, 2011 at 0:27 comment added Qing Liu Very nice and complete answer ! (add $Y$ connected in a) and h)).
Sep 13, 2011 at 23:07 comment added Georges Elencwajg @Mohammad: I have added a bibliography. Point d) is proved in Fischer's book.
Sep 13, 2011 at 23:04 history edited Georges Elencwajg CC BY-SA 3.0
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Sep 13, 2011 at 22:59 history edited Georges Elencwajg CC BY-SA 3.0
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Sep 13, 2011 at 22:28 comment added Mohammad Farajzadeh-Tehrani can give a refernce for (d) or prove it yourself. It is really strong.
Sep 13, 2011 at 22:21 history answered Georges Elencwajg CC BY-SA 3.0