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Georges Elencwajg
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Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open.For example . Hence, contraspositely, the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat.More More generally, the embedding of a closed (and not open !) subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the open map $ Spec(\mathbb C) \to Spec(\mathbb C[\epsilon ]) $ from the reduced point to the double point, which is open but not flat.
[It is not flat because the $\mathbb C[\epsilon]$- algebra $\mathbb C=\mathbb C[\epsilon]/(\epsilon)$ is not flat : recall that a quotient ring $A/I$ can only be flat over $A$ if $I=I^2$ and here $I=(\epsilon) \neq I^2=(\epsilon)^2=(0)$]

An example with both spaces reduced is the normalization [see g) below] $f:X^{nor} \to X $ of the cusp $X\subset \mathbb C^2$ given by the equation $y^2=x^3$ .That normalization is a homeomorphism and so certainly open, but it is not flat : this results either from g) or from h) below.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { locally constant}$$

[Of course for connected $Y$, locally constant = constant]

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open.For example the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat.More generally, the embedding of a closed (and not open !) subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the open map $ Spec(\mathbb C) \to Spec(\mathbb C[\epsilon ]) $ from the reduced point to the double point, which is open but not flat.
[It is not flat because the $\mathbb C[\epsilon]$- algebra $\mathbb C=\mathbb C[\epsilon]/(\epsilon)$ is not flat : recall that a quotient ring $A/I$ can only be flat over $A$ if $I=I^2$ and here $I=(\epsilon) \neq I^2=(\epsilon)^2=(0)$]

An example with both spaces reduced is the normalization [see g) below] $f:X^{nor} \to X $ of the cusp $X\subset \mathbb C^2$ given by the equation $y^2=x^3$ .That normalization is a homeomorphism and so certainly open, but it is not flat : this results either from g) or from h) below.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { locally constant}$$

[Of course for connected $Y$, locally constant = constant]

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open. . Hence, contraspositely, the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat. More generally, the embedding of a closed (and not open !) subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the open map $ Spec(\mathbb C) \to Spec(\mathbb C[\epsilon ]) $ from the reduced point to the double point, which is open but not flat.
[It is not flat because the $\mathbb C[\epsilon]$- algebra $\mathbb C=\mathbb C[\epsilon]/(\epsilon)$ is not flat : recall that a quotient ring $A/I$ can only be flat over $A$ if $I=I^2$ and here $I=(\epsilon) \neq I^2=(\epsilon)^2=(0)$]

An example with both spaces reduced is the normalization [see g) below] $f:X^{nor} \to X $ of the cusp $X\subset \mathbb C^2$ given by the equation $y^2=x^3$ .That normalization is a homeomorphism and so certainly open, but it is not flat : this results either from g) or from h) below.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { locally constant}$$

[Of course for connected $Y$, locally constant = constant]

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

Completely modified b)
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Georges Elencwajg
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Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open.For example the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat.More generally, the embedding of a closed (and not open !) subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the mapopen map $ Spec(\mathbb C) \to Spec(\mathbb C[\epsilon ]) $ from the double point $Spec(\mathbb C[\epsilon ]/(\epsilon^2))\to Spec(\mathbb C)$ fromreduced point to the doubledouble point to the, which is open but not flat.
[It is not flat because the $\mathbb C[\epsilon]$- algebra $\mathbb C=\mathbb C[\epsilon]/(\epsilon)$ is not flat : recall that a quotient ring $A/I$ can only be flat over $A$ if $I=I^2$ and here $I=(\epsilon) \neq I^2=(\epsilon)^2=(0)$]

An example with both spaces reduced point single pointis the normalization [see g) below] $f:X^{nor} \to X $ of the cusp $X\subset \mathbb C^2$ given by the equation $y^2=x^3$ .That normalization is a homeomorphism and so certainly open, but it is not flat : this results either from g) or from h) below.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { locally constant}$$

[Of course for connected $Y$, locally constant = constant]

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open.For example the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat.More generally, the embedding of a closed (and not open !) subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the map from the double point $Spec(\mathbb C[\epsilon ]/(\epsilon^2))\to Spec(\mathbb C)$ from the double point to the reduced point single point.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { locally constant}$$

[Of course for connected $Y$, locally constant = constant]

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open.For example the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat.More generally, the embedding of a closed (and not open !) subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the open map $ Spec(\mathbb C) \to Spec(\mathbb C[\epsilon ]) $ from the reduced point to the double point, which is open but not flat.
[It is not flat because the $\mathbb C[\epsilon]$- algebra $\mathbb C=\mathbb C[\epsilon]/(\epsilon)$ is not flat : recall that a quotient ring $A/I$ can only be flat over $A$ if $I=I^2$ and here $I=(\epsilon) \neq I^2=(\epsilon)^2=(0)$]

An example with both spaces reduced is the normalization [see g) below] $f:X^{nor} \to X $ of the cusp $X\subset \mathbb C^2$ given by the equation $y^2=x^3$ .That normalization is a homeomorphism and so certainly open, but it is not flat : this results either from g) or from h) below.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { locally constant}$$

[Of course for connected $Y$, locally constant = constant]

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

made corrections suggested by Qing Liu
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Georges Elencwajg
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Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open.For example the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat.More generally, the embedding of a closed (and not open !) subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the map from the double point $Spec(\mathbb C[\epsilon ]/(\epsilon^2))\to Spec(\mathbb C)$ from the double point to the reduced point single point.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { constant}$$$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { locally constant}$$

[Of course for connected $Y$, locally constant = constant]

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open.For example the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat.More generally, the embedding of a closed subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the map from the double point $Spec(\mathbb C[\epsilon ]/(\epsilon^2))\to Spec(\mathbb C)$ from the double point to the reduced point single point.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { constant}$$

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

Instead of trying to say what flatness in analytic geometry means I'll give you some street-fighting tricks for recognizing whether a morphism of analytic spaces ( not necessarily reduced) $f:X\to Y $ is , or has a chance to be, flat.

a) A flat map is always open.For example the embedding $\lbrace 0\rbrace \hookrightarrow \mathbb C$ is not flat.More generally, the embedding of a closed (and not open !) subspace $X \hookrightarrow Y$ is never flat.

b) An open map need not be flat: think of the map from the double point $Spec(\mathbb C[\epsilon ]/(\epsilon^2))\to Spec(\mathbb C)$ from the double point to the reduced point single point.

c) Given the morphism $f:X\to Y $ , consider the following property:
$\forall x \in X, \quad dim_x(X)=dim_{f(x)} (Y) +dim_x(f^{-1}(f(x)))$ $\quad (DIM) $
We then have: $ f \; \text {flat} \Rightarrow f \;\text { satisfies } (DIM)$
For example a (non-trivial) blowup is not flat.

d) For a morphism $f:X\to Y $ between connected holomorphic manifolds we have:

$$f \text { is flat} \iff f \text { is open} \quad \iff (DIM) \;\text {holds}$$ For example a submersion is flat, since it is open.

e) Given two complex spaces $X,Y$ the projection $X\times Y\to X$ is flat ( Not trivial: recall that open doesn't imply flat!).

f) flatness is preserved by base change.

g) The normalization $f:X^{nor} \to X $ of a non-normal space is never flat.
For example if $X\subset \mathbb C^2$ is the cusp $y^2=x^3$, the normalization morphism $\mathbb C\to X: t\mapsto (t^2,t^3)$ is not flat.

h) Given a finite morphism $f:X\to Y $, each $y\in Y$ has a fiber $X(y) \subset X$ and for $x\in X$ we can define $\mu (x)= dim_{\mathbb C} (\mathbb C \otimes_{\mathcal O_{Y,y}} \mathcal O_{X,x})$ . Now for $ y\in Y$ we put $\; \nu (y)= \Sigma_{x\in X(y)} \mu(x)$ and we obtain :

$$f \; \text{ flat} \iff \nu :Y\to \mathbb N \text { locally constant}$$

[Of course for connected $Y$, locally constant = constant]

Bibliography:
A. Douady, Flatness and Privilege, L'Enseignement Mathématique, Vol.14 (1968)
G.Fischer, Complex Analytic Geometry, Springer LNM 538, 1976

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Georges Elencwajg
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