Timeline for When are seminormal rings Cohen-Macaulay?
Current License: CC BY-SA 3.0
4 events
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| Sep 8, 2011 at 15:08 | history | edited | Sándor Kovács | CC BY-SA 3.0 |
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| Sep 8, 2011 at 15:06 | comment | added | Sándor Kovács | Yes, that's what I meant. | |
| Sep 8, 2011 at 12:41 | comment | added | Karl Schwede | Three coordinate lines meeting at a point in $\mathbb{A}^3$ is Cohen-Macaulay, but it is not Gorenstein. Three lines through the origin in A^2 is Gorenstein, and as Sandor said, its semi-normalization is not. Thus semi-normalization can make things worse from the perspective of the Gorenstein condition. | |
| Sep 8, 2011 at 11:18 | history | answered | Sándor Kovács | CC BY-SA 3.0 |