Skip to main content
5 events
when toggle format what by license comment
Jan 16, 2014 at 20:34 history edited Bill Johnson CC BY-SA 3.0
Fixed formatting error.
Sep 7, 2011 at 0:45 comment added Bill Johnson Right, Denis, except that there is the additional strange point that you apparently need to keep $\|T^{-1}\|$ bounded.
Sep 6, 2011 at 20:59 comment added Denis Serre Thanks Bill. I see the main point: if $T$ has real eigenvalues, it is similar to $T^*$. In addition, the similarity can be written thanks to a Hermitian change of basis. There remains to choose a $T$ with such an eigenbasis that the similarity is ill-conditioned.
Sep 6, 2011 at 20:55 vote accept Denis Serre
Sep 6, 2011 at 17:39 history answered Bill Johnson CC BY-SA 3.0