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Sep 6, 2011 at 23:07 vote accept Greg Nisbet
Sep 5, 2011 at 21:39 comment added Pietro Majer I'm very curious (yet a bit lazy in this very moment) to know how close is this amazing solution to the largest constant possible in front of $k^2$, which can't be larger than 1/2 if I'm correct.
Sep 5, 2011 at 17:27 vote accept Greg Nisbet
Sep 5, 2011 at 17:27
Sep 5, 2011 at 17:27 vote accept Greg Nisbet
Sep 5, 2011 at 17:27
Sep 5, 2011 at 17:20 history answered Richard Stanley CC BY-SA 3.0