Timeline for Is there some known way to create the Mandelbrot set (the boundary), with an iterated function system?
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Oct 7, 2017 at 21:54 | comment | added | Mr Pie | Look at Numberphile concerning the Mandelbrot Set. It's a YouTube Channel. | |
Mar 6, 2015 at 20:28 | answer | added | Sascha | timeline score: 1 | |
Dec 29, 2011 at 10:45 | vote | accept | Per Alexandersson | ||
Sep 4, 2011 at 23:20 | history | edited | j.c. | CC BY-SA 3.0 |
edit title, tags, capitalize abbreviations
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Sep 4, 2011 at 23:12 | answer | added | Pablo Shmerkin | timeline score: 20 | |
Sep 4, 2011 at 12:45 | history | edited | Per Alexandersson | CC BY-SA 3.0 |
changed some words
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Sep 4, 2011 at 7:31 | history | edited | Per Alexandersson | CC BY-SA 3.0 |
better definition
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Sep 4, 2011 at 7:27 | comment | added | Per Alexandersson | Yes, something like that. I mean, the Julia set is the fixed set for a certain Hutchinson operator, en.wikipedia.org/wiki/Hutchinson_operator with the two functions given above. | |
Sep 3, 2011 at 21:26 | comment | added | Ryan Budney | What do you mean by "create"? If $J_c$ is the Julia set corresponding to $c\in \mathbb C$, let $X_{c,n}$ be the set you create by taking the $n$-th iterate of your 2-valued function $z\longmapsto \sqrt{z−c}$, with the initial iterate being $z_0=0$. Do you want "create" to mean that $\cap_{n=1}^\infty \overline{\cup_{k=n}^\infty X_{c,k}} = J_c$ or something like that? | |
Sep 3, 2011 at 19:13 | history | asked | Per Alexandersson | CC BY-SA 3.0 |