Timeline for What do models where the CH is false look like?
Current License: CC BY-SA 2.5
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 28, 2009 at 4:34 | history | edited | Jason Dyer | CC BY-SA 2.5 |
Simplified.
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| Oct 27, 2009 at 22:18 | answer | added | Tom Leinster | timeline score: 5 | |
| Oct 27, 2009 at 18:46 | answer | added | Grigor | timeline score: 5 | |
| Oct 19, 2009 at 7:50 | answer | added | Kenny Easwaran | timeline score: 13 | |
| Oct 18, 2009 at 9:13 | answer | added | Jeff | timeline score: 2 | |
| Oct 18, 2009 at 8:06 | answer | added | Kenny Easwaran | timeline score: 3 | |
| Oct 16, 2009 at 20:07 | comment | added | John Goodrick | To expand on Richard's comment: if CH is false, then the set of all countable ordinal numbers will be a relatively "natural" set with cardinality between aleph-0 and the continuum. Though we could debate all day about whether or not anybody really knows what this set "looks like"... | |
| Oct 16, 2009 at 20:01 | answer | added | John Goodrick | timeline score: 6 | |
| Oct 16, 2009 at 17:02 | answer | added | Alon Amit | timeline score: 9 | |
| Oct 16, 2009 at 16:17 | comment | added | Richard Dore | I don't understand what you mean by "look like". The first uncountable ordinal will have this property, but I'm not sure if that's what you're looking for. | |
| Oct 16, 2009 at 16:09 | history | edited | Jason Dyer | CC BY-SA 2.5 |
added 9 characters in body
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| Oct 16, 2009 at 16:07 | answer | added | Richard Dore | timeline score: 6 | |
| Oct 16, 2009 at 16:04 | vote | accept | Jason Dyer | ||
| Oct 16, 2009 at 16:04 | answer | added | Andrew Critch | timeline score: 9 | |
| Oct 16, 2009 at 16:02 | answer | added | Eric Wofsey | timeline score: 17 | |
| Oct 16, 2009 at 14:53 | history | asked | Jason Dyer | CC BY-SA 2.5 |