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Sep 1, 2011 at 3:22 vote accept Julia E
Aug 31, 2011 at 16:55 answer added Sergei Ivanov timeline score: 19
Aug 31, 2011 at 15:22 comment added Julia E I really meant shortest representative. I changed the question to reflect that. And I put simple in there because I'm also interested in other metrics on surfaces -- in higher dimensions, the condition is vacuous.
Aug 31, 2011 at 15:21 history edited Julia E CC BY-SA 3.0
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Aug 31, 2011 at 15:13 comment added Jean-Marc Schlenker There is no canonical geodesic representative of a homotopy class of curves in a Riemannian manifold in general (there is one if the curvature is negative). Moreover the notion of homotopy class of simple closed curves does not make sense in dimension larger than 2.
Aug 31, 2011 at 15:05 history asked Julia E CC BY-SA 3.0