Timeline for the blowing up of a plane curve playing me tricks.
Current License: CC BY-SA 3.0
2 events
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Aug 31, 2011 at 6:37 | comment | added | eventually | Thanks for the answer. In the third blowup, the strict transform intersects the exceptional divisor at (0,0) and (0,1). So the point (0,0) is non-singular, but (0,1) is singular!!. If I move that point to the origin, I obtain $x^3(y+1)^4+y^2 = 0$. So, you are saying that I must follow the resolution by blowing at it?. | |
Aug 31, 2011 at 5:53 | history | answered | Michael Joyce | CC BY-SA 3.0 |