Skip to main content
2 events
when toggle format what by license comment
Aug 31, 2011 at 6:37 comment added eventually Thanks for the answer. In the third blowup, the strict transform intersects the exceptional divisor at (0,0) and (0,1). So the point (0,0) is non-singular, but (0,1) is singular!!. If I move that point to the origin, I obtain $x^3(y+1)^4+y^2 = 0$. So, you are saying that I must follow the resolution by blowing at it?.
Aug 31, 2011 at 5:53 history answered Michael Joyce CC BY-SA 3.0