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Aug 28, 2011 at 6:10 vote accept joro
Aug 28, 2011 at 6:08 comment added joro @John Thanks. I am familiar with Sharipov's paper. btw, rational points on his surface do not necessary produce perfect cuboids, there are additional restrictions. Check the conditions in Theorem 5.3 and "...within the open domain $D_{ab}$" Brute force search on Sharipov's surface produced many nontrivial points, but none satisfying the additional conditions.
Aug 27, 2011 at 21:57 comment added Noam D. Elkies Careful: it is not true that a surface of general type always has only finitely many rational points, because it can have rational or elliptic curves that have infinitely many rational points. (Indeed this happens here with the degenerate cuboids having a "side" of length zero.) The Lang-Bombieri conjecture is that all but finitely many points are on such curves, but nobody has any idea how to prove it. Also, reducing modulo $N$ can't work, at least not by itself, because that will not distinguish trivial points (with a zero side) from nontrivial ones.
Aug 27, 2011 at 20:57 history edited John R Ramsden CC BY-SA 3.0
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Aug 27, 2011 at 20:28 history answered John R Ramsden CC BY-SA 3.0