Timeline for adjoint of multiplication operator in a commutative algebra
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 29, 2011 at 7:00 | vote | accept | Tom De Medts | ||
| Aug 29, 2011 at 7:00 | comment | added | Tom De Medts | I'll accept this answer; it's not exactly what I had in mind, but it's definitely very useful --- thanks! | |
| Aug 26, 2011 at 9:02 | comment | added | Tom De Medts | (As pointed out by Dima Shlyakhtenko in his answer ---which is in fact a response to this comment--- this is indeed an additional assumption.) | |
| Aug 25, 2011 at 14:47 | comment | added | Tom De Medts | In $H^*$-algebras, the adjoint of a multiplication operator $L_a$ is always itself a multiplication operator. Is this automatic in the setting that I described, or is this an additional assumption? | |
| Aug 25, 2011 at 12:23 | history | answered | Chris Heunen | CC BY-SA 3.0 |