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May 20, 2020 at 9:51 comment added Martin Sleziak I'll just add the link to Mathematics: Finite index subgroup with free abelianization (as recommended).
May 20, 2020 at 9:43 answer added YCor timeline score: 1
May 20, 2020 at 7:35 history edited YCor CC BY-SA 4.0
added tag, formatting, removed little edit excluding true case.
Aug 25, 2011 at 21:05 answer added Derek Holt timeline score: 9
Aug 25, 2011 at 14:43 comment added Geoff Robinson @Steve: Thanks for clearing that up
Aug 25, 2011 at 14:23 comment added Steve D @Geoff: I believe rank here means the number of $\mathbb{Z}$ summands, i.e., the Betti number.
Aug 25, 2011 at 14:15 vote accept Matthew Clayton
Aug 25, 2011 at 14:10 answer added user6976 timeline score: -1
Aug 25, 2011 at 11:42 history edited Matthew Clayton CC BY-SA 3.0
added 37 characters in body
Aug 25, 2011 at 11:41 comment added Matthew Clayton So the subgroup H would have to be simple non-abelian, and it can't because it's nilpotent? You're right, I'll edit the question.
Aug 25, 2011 at 11:16 history asked Matthew Clayton CC BY-SA 3.0