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Aug 24, 2011 at 19:16 history edited Michael Thaddeus CC BY-SA 3.0
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Aug 24, 2011 at 16:45 comment added Michael Thaddeus It's not, except to describe the ring in which the expression for $k_{PE}$ lies. Since this is in $H^2$, I could have simply said that $H^2(PE,Z)$ is the abelian group freely generated by $H^2(B,Z)$ and $h$. I take your point. Anyway, the expression for $K_{PE}$ is what really matters, and for that, of course, none of this is necessary.
Aug 24, 2011 at 15:05 comment added Damian Rössler @Michael Thaddeus. Where is the Leray-Hirsch theorem actually used here ? Your computation from the second paragraph onwards gives the canonical class, but where do you need the structure of the cohomology of a projectivized bundle ? (other than for fixing ideas)
Aug 24, 2011 at 1:03 history edited Michael Thaddeus CC BY-SA 3.0
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Aug 23, 2011 at 23:46 comment added Dhruv Thats exactly what I was looking for. Thank you.
Aug 23, 2011 at 23:18 history edited Michael Thaddeus CC BY-SA 3.0
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Aug 23, 2011 at 23:17 vote accept Dhruv
Aug 23, 2011 at 23:17 vote accept Dhruv
Aug 23, 2011 at 23:17
Aug 23, 2011 at 23:12 history answered Michael Thaddeus CC BY-SA 3.0