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S Apr 1, 2019 at 22:51 history suggested Ali Taghavi
I add two tags.
Apr 1, 2019 at 21:07 review Suggested edits
S Apr 1, 2019 at 22:51
May 2, 2016 at 18:56 history edited Ben McKay CC BY-SA 3.0
formatting
Aug 23, 2011 at 0:37 vote accept Vamsi
Aug 23, 2011 at 0:25 vote accept Vamsi
Aug 23, 2011 at 0:37
Aug 23, 2011 at 0:08 answer added Robert Bryant timeline score: 25
Aug 22, 2011 at 22:51 history edited Willie Wong CC BY-SA 3.0
removed redundant "enter code here"
Aug 22, 2011 at 22:08 comment added Robert Bryant @David: You mean $F$, not $A$, and this closure is guaranteed by the quasi-Bianchi equation $dF = B\wedge F - F\wedge B$.
Aug 22, 2011 at 22:03 comment added Vamsi The Bianchi identity guarantees this ($dtr(F^k) = ktr(dF F^{k-1})=ktr([B,F]F^{k-1})=0$)
Aug 22, 2011 at 21:49 history edited Gjergji Zaimi
edited tags
Aug 22, 2011 at 21:28 comment added David E Speyer A necessary condition: All the coefficients of the "characteristic polynomial" of $A$ must be closed differential forms. (If we were working over $\mathbb{C}$, these would be the Chern forms. Not sure what they're called over $\mathbb{R}$, but they should be closed either way.)
Aug 22, 2011 at 21:25 history edited Vamsi CC BY-SA 3.0
added 17 characters in body
Aug 22, 2011 at 21:14 history asked Vamsi CC BY-SA 3.0