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Dec 11, 2020 at 15:05 history edited Denis Serre CC BY-SA 4.0
added 8 characters in body
Sep 1, 2011 at 14:46 vote accept JSE
Aug 21, 2011 at 23:42 answer added R W timeline score: 12
Aug 21, 2011 at 23:24 answer added Gjergji Zaimi timeline score: 23
Aug 21, 2011 at 20:23 answer added j.c. timeline score: 9
Aug 21, 2011 at 19:38 comment added Gerhard Paseman Further, the probability of x_{n+d} is zero is bounded below by the probability that x_n is 0 times the probability that y_d is zero for d small and d is the smallest index for which y_k is a general fibonacci sequence and y_d is zero. Perhaps this can be used for a quick and rough estimate. Gerhard "Ask Me About System Design" Paseman, 2011.08.21
Aug 21, 2011 at 19:29 comment added Gerhard Paseman Perhaps you would like to include the observation that the nth term is zero implies n is a multiple of 3? Gerhard "Ask Me About System Design" Paseman, 2011.08.21
Aug 21, 2011 at 19:13 comment added JSE Oh yeah, sorry, doesn't really matter as this induces a global random sign change.
Aug 21, 2011 at 18:47 comment added user6976 In Wiki, the first $\pm$ is missing (in the formula for $X_n$)?
Aug 21, 2011 at 18:33 history asked JSE CC BY-SA 3.0