Timeline for When is a Form a Kähler Form?
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Jul 23, 2017 at 2:53 | comment | added | user21574 | Over a compact complex surface $X$, suppose that a smooth real$ ∂\bar ∂$-closed (1,1)-form $ϕ$ satisfies (1) $∫_Xϕ∧ϕ>0$, (2) $∫_Xϕ∧ω>0 $for a certain positive $∂\bar ∂$-closed (1,1)-form $ω$, and (3) $∫_Dϕ>0$ for any prime divisor $D$ with strictly negative self-intersection; then there is a smooth function $g$ on $X$ such that $ϕ+i∂\bar ∂g$ is positive. This is called Nakai-Moishezon criterion | |
| Jul 17, 2013 at 13:12 | answer | added | Gunnar Þór Magnússon | timeline score: 8 | |
| S Jul 17, 2013 at 8:50 | history | edited | user9072 | CC BY-SA 3.0 |
Added the 'kahler' tag. (changed texlike umlaut to real one)
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| S Jul 17, 2013 at 8:50 | history | suggested | Michael Albanese |
Added the 'kahler' tag.
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| Jul 17, 2013 at 8:47 | review | Suggested edits | |||
| Jul 17, 2013 at 8:50 | |||||
| Aug 21, 2011 at 18:30 | vote | accept | Jean Delinez | ||
| Aug 21, 2011 at 13:56 | answer | added | Spiro Karigiannis | timeline score: 26 | |
| Aug 21, 2011 at 0:20 | comment | added | Spiro Karigiannis | Closedness is the global condition. The only other requirement is that it be a positive (1,1) form. Donu is correct. | |
| Aug 20, 2011 at 22:21 | comment | added | Donu Arapura | Sorry, I don't know of anything like that. | |
| Aug 20, 2011 at 22:16 | comment | added | Jean Delinez | I was hoping for something global | |
| Aug 20, 2011 at 22:03 | comment | added | Donu Arapura | The obvious condition is that it should be a positive $(1,1)$. That is in local coordinates $$\omega = \frac{\sqrt{-1}}{2}\sum h_{ij} dz\wedge d\bar z_j$$ where is $h_{ij}$ is positive definite. | |
| Aug 20, 2011 at 20:57 | history | asked | Jean Delinez | CC BY-SA 3.0 |