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Aug 20, 2011 at 16:47 comment added Did And for $n=3$, $\lambda_1=1/\cos u$, $\lambda_2=\lambda_3=1$, the answer is $\text{cotan}^2(u)−u\text{cotan}^3(u)$. For $\lambda_1=2$, $u=\pi/3$ hence the answer is $(3\sqrt3−\pi)/(9\sqrt3)$.
Aug 20, 2011 at 15:21 history answered Brendan McKay CC BY-SA 3.0