Timeline for Torsion-free tensor powers
Current License: CC BY-SA 3.0
6 events
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| Aug 18, 2011 at 19:17 | comment | added | Jesse Elliott | Nice, indeed! I agree with Martin Brandenburg that there should be an example, which you show must be non finitely generated. | |
| Aug 18, 2011 at 16:31 | comment | added | Hailong Dao | Very nice, +1. It is perhaps worth noting a counter-example in the non-domain case (when torsion-free means that no non-zero element is killed by a regular element). We can take $R= k[x,y]/(xy)$ and $M=R/(x)$. Then $M$ is torsion-free and $M^{\otimes n}=M$ for all $n$. | |
| Aug 18, 2011 at 16:28 | history | edited | David E Speyer | CC BY-SA 3.0 |
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| Aug 18, 2011 at 15:57 | history | edited | David E Speyer | CC BY-SA 3.0 |
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| Aug 18, 2011 at 15:46 | history | edited | David E Speyer | CC BY-SA 3.0 |
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| Aug 18, 2011 at 15:19 | history | answered | David E Speyer | CC BY-SA 3.0 |