Timeline for Units of time in the gradient flow equation?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 7, 2011 at 16:18 | vote | accept | Chong Luo | ||
| Aug 30, 2011 at 10:09 | vote | accept | Chong Luo | ||
| Aug 30, 2011 at 10:09 | |||||
| Aug 30, 2011 at 10:08 | vote | accept | Chong Luo | ||
| Aug 30, 2011 at 10:08 | |||||
| Aug 17, 2011 at 16:33 | vote | accept | Chong Luo | ||
| Aug 30, 2011 at 10:07 | |||||
| Aug 17, 2011 at 16:18 | answer | added | Carlo Beenakker | timeline score: 4 | |
| Aug 17, 2011 at 15:47 | comment | added | Steve Huntsman | By the gradient flow equation, $[K] = L^2 T^{-1}$, where length and time are indicated. Meanwhile the Oseen-Frank "energy" (call it $\mathcal{E}$) has unit $[K] L^{-2} = T^{-1}$, not the physical energy unit $E = M L^2 T^{-2}$. This sort of elision of units is fairly typical of mathematical practice. Note that the unit of action is $[\hbar] = E T$, so $[\hbar \mathcal{E}] = E$. | |
| Aug 17, 2011 at 14:34 | history | asked | Chong Luo | CC BY-SA 3.0 |