Timeline for What does $L^\infty_\varepsilon$ mean?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Aug 28, 2011 at 8:00 | comment | added | Helge | On another note: It seems to me that this question is answered to the authors satisfaction? Is there some way to stop from making it come back to the top? | |
| Aug 28, 2011 at 7:59 | comment | added | Helge | Noam: It should be $\sqrt{-1}$, since that works for any self-adjoint operator. But since the (negative) Laplacian $-\Delta$ is positive, one could also take $-\Delta + Identity$. This choice is sometimes made to preserve reality. | |
| Aug 27, 2011 at 19:09 | comment | added | Noam D. Elkies | In the definition of "relatively compact" are you inverting $-\Delta - i$ (with $i=\sqrt{-1}$) or $-\Delta - I$ (with $I$ the identity operator)? | |
| Aug 13, 2011 at 17:38 | history | answered | Hapless reader | CC BY-SA 3.0 |