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Henri
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Take the most simple example $M=\mathbb C$ and $X$ the unit circle. Then $d_X(z)=|z-\frac{z}{|z|}|^2$ is not holomorphic (so as its Laplacian $i\partial \bar \partial( d_X)$), as you can easily see by expanding the expression.

Take the most simple example $M=\mathbb C$ and $X$ the unit circle. Then $d_X(z)=|z-\frac{z}{|z|}|^2$ is not holomorphic as you can easily see by expanding the expression.

Take the most simple example $M=\mathbb C$ and $X$ the unit circle. Then $d_X(z)=|z-\frac{z}{|z|}|^2$ is not holomorphic (so as its Laplacian $i\partial \bar \partial( d_X)$), as you can easily see by expanding the expression.

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Henri
  • 2.7k
  • 1
  • 18
  • 17

Take the most simple example $M=\mathbb C$ and $X$ the unit circle. Then $d_X(z)=|z-\frac{z}{|z|}|^2$ is not holomorphic as you can easily see by expanding the expression.