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Feb 25, 2013 at 2:01 vote accept Asaf Karagila
Aug 9, 2011 at 12:10 comment added Asaf Karagila @Joel: Thanks a lot. If I get it correct then in the supercompact case we have that it is never an internal embedding. But if we reduce ourselves to $\lambda=\kappa$ (which is essentially the measurable case again) then it is possible for the embedding to be internal, can we deduce anything on the relationship in the Mitchell order between the original measure and the normal one? (Assuming, of course, the original $M$ is an ultrapower itself)
Aug 9, 2011 at 11:54 history edited Joel David Hamkins CC BY-SA 3.0
Corrected typo
Aug 9, 2011 at 9:45 history answered Joel David Hamkins CC BY-SA 3.0