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Apr 9, 2020 at 14:52 comment added Lao-tzu @Anton Geraschenko I think I can prove it now using degree formula.
Apr 9, 2020 at 14:36 comment added Lao-tzu @Anton Geraschenko Is the finite etale map $(Y\times_X Y -\Delta)\to Y$ surjective (if $deg(\pi)>1$)? I think you need this to see that the $U$ you get in the end turns out to be an etale cover of $X$. I'm unable to show this.
Jan 2, 2013 at 14:58 comment added Anton Geraschenko @ZhuangXiaobo: Let's work locally, so that the map is $Spec(S)\to Spec(R)$. By definition, "degree $n$" means that the corresponding ring homomorphism $R\to S$ makes $S$ into a free module of rank $n$ over $R$. If $n=1$, the map is bijective, so an isomorphism of rings.
Jan 2, 2013 at 2:30 comment added Xiaobo Zhuang @Anton Geraschenko:How to see an finite etale morphism of degree one is an isomorphism? I think you use this fact in your answer.
Aug 8, 2011 at 17:44 history edited Qfwfq CC BY-SA 3.0
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Aug 8, 2011 at 16:38 comment added Anton Geraschenko It's worth pointing out that it's a general philosophy that things that you expect to be true because of your experience with the analytic topology are usually true in the etale topology.
Aug 8, 2011 at 16:26 comment added Akhil Mathew Another way to see the last fact is to note that finite etale covers of a strictly henselian ring are split, together with the fact that the strict henselianization at a point is the "limit" of etale neighborhoods (and a "noetherian descent" argument to argue that the splitting must descend to some etale neighborhood after all).
Aug 8, 2011 at 16:07 vote accept Jesko Hüttenhain
Aug 8, 2011 at 16:00 history answered Anton Geraschenko CC BY-SA 3.0