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Aug 9, 2011 at 0:22 comment added Tom Leinster OK, sorry not to have added anything new. (Personally I find this fact of Schoenberg's rather surprising, in that the triangle inequality doesn't have to be mentioned.) I'm afraid I don't have any further thoughts.
Aug 8, 2011 at 22:56 comment added Sunni +1, Thanks, I know this fact. Do you think if it is possible to characterize the orthogonal matrix $P$ such that $P^TMP$ is diagonal?
Aug 8, 2011 at 14:55 history answered Tom Leinster CC BY-SA 3.0