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Corrected the interchange of X and Y; added 1 characters in body
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Bill Johnson
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Use $\sum 2^{-n}(\|x-y\|_n \wedge 1)$ for the distance on $X$$Y$ and $\sum 2^{-n}(\|x-y\|_n \wedge 2)$ for the distance on $Y$$X$.

Use $\sum 2^{-n}(\|x-y\|_n \wedge 1)$ for the distance on $X$ and $\sum 2^{-n}(\|x-y\|_n \wedge 2)$ for the distance on $Y$.

Use $\sum 2^{-n}(\|x-y\|_n \wedge 1)$ for the distance on $Y$ and $\sum 2^{-n}(\|x-y\|_n \wedge 2)$ for the distance on $X$.

Source Link
Bill Johnson
  • 31.5k
  • 5
  • 89
  • 138

Use $\sum 2^{-n}(\|x-y\|_n \wedge 1)$ for the distance on $X$ and $\sum 2^{-n}(\|x-y\|_n \wedge 2)$ for the distance on $Y$.