Timeline for Ultrapowers by normalized ultrafilters
Current License: CC BY-SA 3.0
3 events
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| Aug 4, 2011 at 20:15 | comment | added | Ali Enayat | @Andreas: your characterization can be fine-tuned by adding $Ult(V,U)=M$ precisely when every element of $M$ is definable in $M$ by a first order formula whose parameters are allowed to come from {$\kappa$} $\cup$ the range of $j$. | |
| Aug 4, 2011 at 19:38 | comment | added | Asaf Karagila♦ | Now that you mention that, I think that I may have seen this sort of example of why $M$ need not be equal to $\operatorname{Ult}(V,U)$. Many thanks for the answer! | |
| Aug 4, 2011 at 19:33 | history | answered | Andreas Blass | CC BY-SA 3.0 |