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Jun 15 at 14:09 comment added Kuzja Maybe I am missing something, but the function $\frac{x+y}{2}$ doesn't form a Latin square. $(2k + 2) \cdot \frac{x+y}{2} \text{ mod } 2k + 1 = (k +1)(x+y) \text{ mod } 2k + 1$, however, does.
Aug 9, 2011 at 13:48 vote accept JarvisP
Aug 4, 2011 at 14:47 history answered David E Speyer CC BY-SA 3.0