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Aug 5, 2011 at 9:04 answer added Martin Brandenburg timeline score: 5
Aug 5, 2011 at 8:57 comment added darij grinberg Thanks. I assume this easily follows from "finite projective modules are direct addends of finite free modules".,
Aug 5, 2011 at 4:19 comment added Mahdi Majidi-Zolbanin Regarding the second part of your question, where $k$ is a commutative ring with $1$ and $A,B,C,D$ are $k$-modules, you can find a partial answer in Bourbaki's Algebra (Chapter II, No. 4, Proposition 4), where it is proved that if one of the pairs (A,B), or (A,C), or (B,D) consists of finite projective modules, then the canonical map in question is in fact bijective.
Aug 3, 2011 at 18:21 history edited darij grinberg CC BY-SA 3.0
added reference, now that I know that the only person I am shaming is myself
Aug 3, 2011 at 18:18 vote accept darij grinberg
Aug 3, 2011 at 18:14 history edited Anton Geraschenko CC BY-SA 3.0
edited title for readability
Aug 3, 2011 at 18:10 answer added user2035 timeline score: 28
Aug 3, 2011 at 18:07 answer added Mahdi Majidi-Zolbanin timeline score: 0
Aug 3, 2011 at 17:17 history asked darij grinberg CC BY-SA 3.0