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Jul 31, 2011 at 17:16 comment added Francesco Polizzi On a smooth surface the answer is certainly yes, since any divisor is lineraly equivalent to the difference of two very ample divisors. Of course, the divisor $E$ lineraly equivalent to $D$ and avoiding $X$ will not be effective in general. But the OP does not require effectiveness. In your example, it is sufficient to take $E=L-F$, where $L$ is the strict transform of a general line and $F$ the strict transform of a line passing to the point you are blowing up.
Jul 31, 2011 at 17:10 vote accept Ariyan Javanpeykar
Jul 31, 2011 at 17:05 history answered J.C. Ottem CC BY-SA 3.0