Timeline for Open affine subscheme of affine scheme which is not principal
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 29, 2009 at 20:24 | comment | added | Charles Siegel | Ahh, now I see what you mean. | |
| Nov 29, 2009 at 20:22 | comment | added | Wanderer | But it's not affine, and that's really the point of the question! | |
| Nov 29, 2009 at 20:20 | comment | added | Charles Siegel | My answer still works. There is no function $f\in k[x,y]$ such that $f=0$ iff $x=y=0$, so $\mathbb{A}^2\setminus\{0\}$ is not determined by the nonvanishing of a single function. | |
| Nov 29, 2009 at 20:18 | comment | added | Wanderer | I clarified my question... Sorry for being a bit vague. But your answer doesn't work, obviously. | |
| Nov 29, 2009 at 20:06 | history | answered | Charles Siegel | CC BY-SA 2.5 |