Timeline for Self-adjoint bounded operator, resolution of the identity, def. of the diagonal
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Aug 1, 2011 at 22:09 | comment | added | Martin Argerami | Thanks, Mikael, I had not paid attention to the word "continuous" in the question. Now it's obvious: if $A$ generates a diffuse masa, then this masa cannot contain any finite-dimensional projections. | |
| Aug 1, 2011 at 11:22 | comment | added | Mikael de la Salle | Martin: I do not see any contradiction. This would just prove that (under the appropriate hypotheses) the only compact operator commuting with $A$ is $0$. | |
| Jul 31, 2011 at 7:15 | answer | added | Dima Shlyakhtenko | timeline score: 3 | |
| Jul 30, 2011 at 18:49 | comment | added | Martin Argerami | I don't think that $Diag(B)=0$ when $B$ is compact. What happens if $B$ is compact and commutes with $A$? | |
| Jul 28, 2011 at 21:06 | comment | added | user2171 | Yakov, I bet all Russian speaking users of MO are OK with English. | |
| Jul 28, 2011 at 20:41 | history | edited | Yakov Dymarskii | CC BY-SA 3.0 |
added 1197 characters in body; edited title
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| Jul 28, 2011 at 20:18 | history | asked | Yakov Dymarskii | CC BY-SA 3.0 |