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Feb 27, 2023 at 15:32 history edited darij grinberg CC BY-SA 4.0
maybe an edit will fix the kitty bug
Oct 30, 2011 at 23:13 answer added Vladimir Dotsenko timeline score: 3
Oct 30, 2011 at 17:24 answer added Pasha Zusmanovich timeline score: 1
Oct 19, 2011 at 17:56 history edited probably CC BY-SA 3.0
major update; edited tags
Aug 8, 2011 at 18:18 answer added Pasha Zusmanovich timeline score: 2
Jul 25, 2011 at 17:59 comment added Suvrit Here's a random junk idea: we work with halves throughout. Define $f(a,b) = 0.5[a,b]+ 0.5(ab+ba)$, and define $f^T$ to be the half-transpose $0.5[b,a^T]+0.5(ba^T+a^Tb)$. Then, $a\square b = 0.5(f + f^T)$.
Jul 25, 2011 at 0:08 history edited probably CC BY-SA 3.0
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Jul 24, 2011 at 19:45 history edited probably
edited tags
Jul 24, 2011 at 19:36 comment added probably No, i do not consider the transpose as a separate operation in that variety of algebras. Also i can accept an axiomatisation that is not exact, but give rise to some interesting class. Like "if you see an anticommutator then think on Jordan algebras".
Jul 24, 2011 at 19:21 comment added Qiaochu Yuan Do you also want to consider the transpose in this axiomatization? (Also, it's not clear to me that Jordan algebras are the correct axiomatization of the anticommutator: it's known that exceptional Jordan algebras exist which aren't embeddable into matrix Jordan algebras.)
Jul 24, 2011 at 19:06 history edited probably CC BY-SA 3.0
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Jul 24, 2011 at 19:00 history asked probably CC BY-SA 3.0