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Jul 20, 2011 at 1:28 comment added paul garrett Hm! So RH is somewhat more potentially negate-able than I'd thought! Not that I expect to do so... :)
Jul 19, 2011 at 22:16 comment added GH from MO Once I verified that Schoenfeld's result implies $|\pi(x)-li(x)|<x^{1/2}\log x$ for all $x>2$.
Jul 19, 2011 at 21:31 comment added Stopple @Paul, I just looked up the Schoenfeld result: On RH, $|\pi(x)-li(x)|$ is less than $x^{1/2}\log(x)/(8\pi)$ for $2,657\le x$, no mention that this is optimal.
Jul 19, 2011 at 21:07 comment added paul garrett First, in response to @Stopple's recollection: if this is true everywhere, not merely asymptotically, then it is testable!?! As to the meaning of big-Oh, it means bounded by a constant multiple of...
Jul 19, 2011 at 20:52 comment added André Henriques I'm confused by all your comments above. The big-O notation means that the error term is bounded by $\sqrt{x}\log(x)$, not that it's asymptotically proportional to it. See en.wikipedia.org/wiki/Big_O_notation.
Jul 19, 2011 at 20:52 answer added David E Speyer timeline score: 7
Jul 19, 2011 at 20:33 comment added Stopple On the Riemann Hypothesis, Schoenfeld showed the constant $C$ can be taken as $1/(8\pi)$, and (iirc) this can not be improved on.
Jul 19, 2011 at 20:21 answer added GH from MO timeline score: 12
Jul 19, 2011 at 20:04 comment added user16557 Oh ok I was under the misimpression that the constant was known.
Jul 19, 2011 at 20:03 history undeleted user16557
Jul 19, 2011 at 20:03 history deleted user16557
Jul 19, 2011 at 19:58 comment added Qiaochu Yuan No, one would expect it would come near $C \sqrt{x} \log x$ for an appropriate constant.
Jul 19, 2011 at 19:57 history asked user16557 CC BY-SA 3.0