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Jul 30, 2011 at 10:24 vote accept Ian Morris
Jul 19, 2011 at 11:09 comment added Ian Morris I was quite careful with my phrasing so as not to exclude cases such as this: the example $f_n(x)=\sqrt{n}$ does indeed return infinitely often to some neighbourhood of 0 which is not a neighbourhood of $-\infty$, namely the open neighbourhood $(−1,+\infty)$.
Jul 19, 2011 at 6:59 comment added Anthony Quas The supposed equivalent statement is false by the same counterexample I mentioned to Vaughan below: $f_n(x)=sqrt n$ (!)
Jul 19, 2011 at 3:26 answer added Vaughn Climenhaga timeline score: 3
Jul 18, 2011 at 21:34 history edited Ian Morris CC BY-SA 3.0
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Jul 18, 2011 at 21:27 history asked Ian Morris CC BY-SA 3.0