Skip to main content
2 events
when toggle format what by license comment
Jul 16, 2011 at 16:02 comment added Torsten Ekedahl The Hodge index theorem gives you that $K^2_SC^2\le(C\cdot K_S)^2$.
Jul 16, 2011 at 13:41 history asked Luca Benzo CC BY-SA 3.0