Timeline for Finitely generated subgroup [closed]
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 11, 2017 at 23:09 | vote | accept | Adterram | ||
| Dec 4, 2015 at 12:51 | comment | added | YCor | @user83632 BTW if you ask a question in these terms, it will be put on hold as unclear (you have to explain your notation). | |
| Dec 4, 2015 at 11:49 | history | closed |
YCor Stefan Kohl♦ Ryan Budney Wolfgang Frieder Ladisch |
Needs more focus | |
| Dec 4, 2015 at 10:20 | review | Close votes | |||
| Dec 4, 2015 at 11:49 | |||||
| Dec 4, 2015 at 9:37 | comment | added | user83632 | Let $Z=\gamma_s(G)\cap Z(G)$. Why if $\gamma_s(G)/Z$ is finite then there exists a finitely generated subgroup $U$ of $G$ such that $\gamma_s(G)=\gamma_s(U)Z$? | |
| Jul 12, 2011 at 19:21 | comment | added | Ian Agol | The class of slender groups is closed under taking subgroups, quotients, and finite products. If it were closed under taking direct products, then it would form a variety, but this is not the case. en.wikipedia.org/wiki/Variety_(universal_algebra) It's also closed under taking extensions. This is very closely related to an extension closed variety of finite groups, but I'm not sure what's been considered in the infinite group case. | |
| Jul 12, 2011 at 18:20 | comment | added | Ian Agol | related question: mathoverflow.net/questions/26059/… | |
| Jul 12, 2011 at 13:42 | answer | added | HJRW | timeline score: 2 | |
| Jul 12, 2011 at 9:15 | comment | added | HJRW | This question is absurdly broad. As it clearly has no single answer, it should certainly be community wiki. | |
| Jul 12, 2011 at 8:46 | answer | added | Yiftach Barnea | timeline score: 2 | |
| Jul 12, 2011 at 7:55 | answer | added | Max Horn | timeline score: 5 | |
| Jul 12, 2011 at 7:01 | answer | added | Martin Brandenburg | timeline score: 9 | |
| Jul 12, 2011 at 6:43 | history | asked | Adterram | CC BY-SA 3.0 |