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Jul 12, 2011 at 13:54 comment added Michal Zydor I got two ideas confused for a while, now I understand your answer, thanks.
Jul 12, 2011 at 13:52 vote accept Michal Zydor
Jul 12, 2011 at 12:47 comment added Jason Starr It depends on what is being asked. In the post, it is asked why this subset of $\prod_{k=-\infty}^{\infty} k$ is not an algebraic subset. That is the question I answered. The separate question, is there some way of making this set a scheme, is not the one answered.
Jul 12, 2011 at 6:27 comment added Martin Brandenburg Yes this proof is incomplete.
Jul 11, 2011 at 22:00 comment added Michal Zydor Thanks, I was sure I had understood, but now I have doubts though. Doesn't it only show that $k((\epsilon))$ is not affine? But, anyway, you made me realize that I was missing one thing - $\epsilon^ik[[\epsilon]]$ are closed in $k((\epsilon))$.
Jul 11, 2011 at 21:27 vote accept Michal Zydor
Jul 11, 2011 at 22:01
Jul 11, 2011 at 20:13 history answered Jason Starr CC BY-SA 3.0