Timeline for Jonsson Boolean algebras?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 23, 2018 at 14:46 | comment | added | Joel David Hamkins | Yes, thanks for pointing it out. I enjoyed the lunch in Prague today very much, rabbit with potatoes and cabbage, plus beer. It seemed all very Czech. | |
| Jan 23, 2018 at 14:38 | comment | added | Tomasz Kania | This is the question I mentioned over lunch today. :-) | |
| Jul 12, 2011 at 1:57 | comment | added | Juris Steprans | More generally, no abelian group of finite exponent (and hence no Boolean algebra) is Jonsson. To see this, simply note that any element is contained in a countable pure subgroup and pure subgroups of finite exponent are direct summands. So an uncountable such group will always have a non-trivial uncountable direct summand. | |
| Jul 11, 2011 at 23:01 | comment | added | Joel David Hamkins | Yes, Ali, it seems to work in any infinite cardinality. | |
| Jul 11, 2011 at 22:56 | comment | added | Ali Enayat | I think your proof can be also used to show that there are no countably infinite Jonsson BAs. In other words, you have shown that Jonsson BA's are precisely finite BAs. | |
| Jul 11, 2011 at 17:41 | vote | accept | Tomasz Kania | ||
| Jul 11, 2011 at 17:33 | history | answered | Joel David Hamkins | CC BY-SA 3.0 |